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Exercício de Eletroestática
Exercício:
Olá pessoas, a questão é a seguinte:
Devido ao balanceamento entre cargas elétricas positivas e negativas nos objetos e seres vivos, não se observam forças elétricas atrativas ou repulsivas entre eles, em distâncis macroscópicas. Para se ter, entretanto, uma ideia da intensidade da força gerada pelo desbalanceamento de cargas, considere duas pessoas com mesma altura e peso separadas pela mesma distância de 0,8m. Supondo que cada um possui um excesso de prótons correspondentes a 1% de sua massa, a estimativa da intensidade da força elétrica resultante desse desbalanceamento de cargas e da massa que resultará numa força-peso de igual intensidade são respectivamente:
Resposta: 60×1024N e 6×1024 kg
Informações Adicionais:
Para resolver a questão é preciso saber a massa do próton, que é esta: 1,7×10^(-27)
Pesquisando pela internet, acabei vendo uma resolução usando a massa como 1,6×10^(-27)
Usando as duas massas eu não cheguei a alternativa correta. Com a massa do próton 1,7×10^(-27) cheguei a Força Elétrica de 5,76×10^25.
Ajudem-me, por favor, odeio ficar com questões não esclarecidas. :/
primeiro determinar a massa de prótons exedentes:
1% de 70kg = 0,7 kg de prótons
o numero de próton
1 próton = 1,7 x 10-27
n prótons = 0,7
logo: n = 4,1 x 1026
Para determinar a força elétrica é necessario a carga (Q)
Q= ne = 4,1 x 1026 * 1,6 x 10-19= 6,56 x 107
Aplicando na fórmula
F = (KQq)/d2
sabendo que k = 9 x 109
Agora é só voce finalisar
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