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	<title>Comments on: Funcão horaria</title>
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	<description>Exercícios para o Vestibular</description>
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	<item>
		<title>By: Ítalo</title>
		<link>http://www.amigonerd.com/funcao-horaria/comment-page-1/#comment-41977</link>
		<dc:creator>Ítalo</dc:creator>
		<pubDate>Thu, 01 Sep 2011 17:12:16 +0000</pubDate>
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		<description>A dist&#226;ncia entro o caminh&#227;o e o jipe esta em metros e por isso a velocidade dever&#225; ser em m/s e nau, em km/h.
A=Caminh&#227;o, B=Jipe
VA=54km/s=15m/s
VB=72km/h=20m/s
&#160;
SA=100+15t
SB=0+20t



&lt;strong&gt;Instante em q o Jipe alcan&#231;a o Caminh&#227;o&lt;/strong&gt;
SA=SB
100+15t=0+20t
100-0=20t-15t
100=5t
t=100/5
&lt;strong&gt;t=20&lt;/strong&gt;
&#160;
&lt;strong&gt;R.: O Jipe alcan&#231;ar&#225; o caminh&#227;o depois de 20 segundos.&lt;/strong&gt;



&lt;strong&gt;Caminho do Jipe&lt;/strong&gt;
&#916;V=&#916;S0-&#916;S/&#916;T
20=0-x/20
20*20=x
&lt;strong&gt;x=400&lt;/strong&gt;
&lt;strong&gt;R.: O caminho percorrido pelo Jipe at&#233; alcan&#231;ar o caminh&#227;o &#233; de 400 metros.&lt;/strong&gt;
&#160;
&#160;
&#160;</description>
		<content:encoded><![CDATA[<p>A dist&acirc;ncia entro o caminh&atilde;o e o jipe esta em metros e por isso a velocidade dever&aacute; ser em m/s e nau, em km/h.<br />
A=Caminh&atilde;o, B=Jipe<br />
VA=54km/s=15m/s<br />
VB=72km/h=20m/s<br />
&nbsp;<br />
SA=100+15t<br />
SB=0+20t</p>
<p><strong>Instante em q o Jipe alcan&ccedil;a o Caminh&atilde;o</strong><br />
SA=SB<br />
100+15t=0+20t<br />
100-0=20t-15t<br />
100=5t<br />
t=100/5<br />
<strong>t=20</strong><br />
&nbsp;<br />
<strong>R.: O Jipe alcan&ccedil;ar&aacute; o caminh&atilde;o depois de 20 segundos.</strong></p>
<p><strong>Caminho do Jipe</strong><br />
&Delta;V=&Delta;S0-&Delta;S/&Delta;T<br />
20=0-x/20<br />
20*20=x<br />
<strong>x=400</strong><br />
<strong>R.: O caminho percorrido pelo Jipe at&eacute; alcan&ccedil;ar o caminh&atilde;o &eacute; de 400 metros.</strong><br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
]]></content:encoded>
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	<item>
		<title>By: William</title>
		<link>http://www.amigonerd.com/funcao-horaria/comment-page-1/#comment-41303</link>
		<dc:creator>William</dc:creator>
		<pubDate>Sat, 27 Aug 2011 22:05:06 +0000</pubDate>
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		<description>100+54t=x
72t=x
t=5,5h
x=396m</description>
		<content:encoded><![CDATA[<p>100+54t=x<br />
72t=x<br />
t=5,5h<br />
x=396m</p>
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