Comments on: Logarítmo http://www.amigonerd.com/logaritmo/ Exercícios para o Vestibular Thu, 09 Feb 2012 03:08:26 +0000 hourly 1 http://wordpress.org/?v=3.0.1 By: lauisa http://www.amigonerd.com/logaritmo/comment-page-1/#comment-54259 lauisa Thu, 22 Dec 2011 13:06:26 +0000 http://www.amigonerd.com/?p=35839#comment-54259 log 2 = m e log 3= n e log 108? log 2 = m e log 3= n e log 108?

]]> By: Wellington http://www.amigonerd.com/logaritmo/comment-page-1/#comment-53665 Wellington Tue, 13 Dec 2011 02:08:39 +0000 http://www.amigonerd.com/?p=35839#comment-53665 log(2+3)&sup2; * log 3&sup2; -> 2log2 * 2log3 * 2log3 -> <strong>2a * 4b</strong> log(2+3)&sup2; * log 3&sup2; -> 2log2 * 2log3 * 2log3 -> 2a * 4b

]]> By: Rosane Alves http://www.amigonerd.com/logaritmo/comment-page-1/#comment-53643 Rosane Alves Mon, 12 Dec 2011 21:20:36 +0000 http://www.amigonerd.com/?p=35839#comment-53643 log27=xx log27=xx

]]> By: Rosane Alves http://www.amigonerd.com/logaritmo/comment-page-1/#comment-53641 Rosane Alves Mon, 12 Dec 2011 21:18:25 +0000 http://www.amigonerd.com/?p=35839#comment-53641 log1251/5 log1251/5

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