<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: solução tampão</title>
	<atom:link href="http://www.amigonerd.com/solucao-tampao/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.amigonerd.com/solucao-tampao/</link>
	<description>Exercícios para o Vestibular</description>
	<lastBuildDate>Thu, 09 Feb 2012 03:08:26 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.0.1</generator>
	<item>
		<title>By: Francisco</title>
		<link>http://www.amigonerd.com/solucao-tampao/comment-page-1/#comment-56117</link>
		<dc:creator>Francisco</dc:creator>
		<pubDate>Tue, 07 Feb 2012 14:18:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.amigonerd.com/?p=11096#comment-56117</guid>
		<description>Impossivel de calcular.
Precisas pelo menos o valor do pka para poder calcular o ph aplicando pela formula:
ph=pka + log NH4OH/NH4(Cl)</description>
		<content:encoded><![CDATA[<p>Impossivel de calcular.<br />
Precisas pelo menos o valor do pka para poder calcular o ph aplicando pela formula:<br />
ph=pka + log NH4OH/NH4(Cl)</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Vanessa</title>
		<link>http://www.amigonerd.com/solucao-tampao/comment-page-1/#comment-18869</link>
		<dc:creator>Vanessa</dc:creator>
		<pubDate>Sat, 30 Oct 2010 18:30:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.amigonerd.com/?p=11096#comment-18869</guid>
		<description>v=200ml M=0,12M NH4OH(base fraca)
v=400ml m=1,2M Nh4Cl(sal correspondente)
tamp&#227;o b&#225;sico pH maior que 7 (pois adv&#233;m de uma base fraca e sal correspontente)
v1.m1+v2.m2=vf.mf
0,2.0.12+0.4.1.2=0.6.mf
mf=0,84M= 84.10-1&#160;
&#160;
&#160;</description>
		<content:encoded><![CDATA[<p>v=200ml M=0,12M NH4OH(base fraca)<br />
v=400ml m=1,2M Nh4Cl(sal correspondente)<br />
tamp&atilde;o b&aacute;sico pH maior que 7 (pois adv&eacute;m de uma base fraca e sal correspontente)<br />
v1.m1+v2.m2=vf.mf<br />
0,2.0.12+0.4.1.2=0.6.mf<br />
mf=0,84M= 84.10-1&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: flAVIO</title>
		<link>http://www.amigonerd.com/solucao-tampao/comment-page-1/#comment-18657</link>
		<dc:creator>flAVIO</dc:creator>
		<pubDate>Thu, 28 Oct 2010 13:20:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.amigonerd.com/?p=11096#comment-18657</guid>
		<description>COMO RESOLVE ESETE EXERCICIO TENHO MUITA DUVIDA. ACHO QUE NAO COMPREENDO BEM O CONCEITO PARA APLICA OS CAUCULOS</description>
		<content:encoded><![CDATA[<p>COMO RESOLVE ESETE EXERCICIO TENHO MUITA DUVIDA. ACHO QUE NAO COMPREENDO BEM O CONCEITO PARA APLICA OS CAUCULOS</p>
]]></content:encoded>
	</item>
</channel>
</rss>

