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Exercício de Construa o gráfico das equações abaixo
Exercício:
a) 2x -y= -1
b) x+2y= 5
c) 2x -y=-2
d) x+ y= 12
e) x= 2y
f) y= 3x
g) x-y = -6
h) x+3y = 11
Informações Adicionais:
Tenho dificuldade matéria e quero ajuda.
Bem simples, amigo. Vamos lá.
Essa matéria é funções, para montar o gráfico de funções no plano cartesiano, é necessário que tu saiba algumas funções-chave, para facilitar e dar dinâmica pra resolver um exercício.
Por exemplo, no gráfico de uma reta simples, a “fórmula” básica é:
f(x) = ax + b
Ou seja, f(x) representa o Y no gráfico (ou a reta vertical, eixo das ordenadas)
Ax (lê A vezes X) representa o coeficiente angular dessa reta, o quão inclinada ela estará em relação ao eixo horizontal (eixo das abscissas).
Se o a for positivo, a reta sobe. Se o a for negativo, a reta estará descendo.
O B é o termo independente, basicamente em que posição a reta corta o eixo dos Y. Para descobrir o B, basta igualar a função de reta ao zero
Exemplo: f(x) = ax + b —> f(0) = a . 0 + b —-> f(0) = b
Agora, para o primeiro exercício.
2x – y = -1
Seu primeiro passo será isolar o Y de forma que ele fique positivo
Passe o Y para o outro lado da igualdade, dessa forma
2x – y = -1
2x = y – 1
Passe também o 1, para que o Y possa realmente estar sozinho
2x + 1 = y (lembre-se que ao mudar de lado da igualdade, o sinal também muda)
Reorganizando, a equação fica: y = 2x + 1 ou f(x) = 2x + 1
É uma reta que sobe (a é positivo) e que corta o eixo do Y no 1.
Outra sugestão: Vá adicionando alguns pontos, toda função é uma máquina que transforma o número que tu coloca. Isso é, ao colocar o número 2 na função f(x) = 2x + 1, você obtém o número 5
f(2) = 2.2 + 1 = 4 + 1 = 5
Faça com os números -3, -2, -1, 0, 1, 2 e 3, isso te dará uma parte do que é o gráfico da função em questão, sempre lembrando que f(x) é a mesma coisa que Y.
Espero que tenha entendido, infelizmente não tem como desenhar aqui, mas acredito que com essa explicação fica fácil desenhar o restante.
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