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Exercício de Estrutua Atômica
por Lucas (FEI - SP)
Difícil Sunday, July 25th, 2010
Exercício:
Num exercício escolar, um professor pediu a cada aluno que imaginasse um átomo que tivesse o número atômico igual do seu número de chamada, e o número de nêutrons duas unidades a mais que o número de prótons. O aluno nº 15 se esqueceu de somar 2 para obter o número de nêutrons e consequentemente, dois alunos imaginaram átomos isóbaros.
Determine os números de chamada dos alunos com quem esse fato ocorreu.
Informações Adicionais:
Sei que Z = p e que A = p + n Consequentimente A = Z + n.
Como n = Z + 2 então n = p + 2, temos:
1º aluno – A = 30, pois ele esqueceu de adcionar 2 no número atômico, ficando Z = n, logo Z = 15 e n = 15.
2º aluno – A = 30, pois estes são isobaros, com isso temos A = Z + n substituindo temos: 30 = Z + (Z + 2), como sugerido no enunciado, temos 30 = 2.Z + 2; 30 – 2 = 2.Z; 28 = 2.Z; Z = 14.
Conclusão: O 1º aluno possui número de chamada igual a 15 e o 2º alunos possui número de chamada igual a 14.
Comprovação: A = 14 + (14 + 2) = 14 + 16 = 30 então A = 30 para o 2º aluno.
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