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Exercício de grandezas quimicas
Exercício:
a analise da vitamina B12 mostra que ela é constituida de 4,34% de colbato, quantos atomos de cobalto existem em 1,5 g de vitamina b12 ?
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Bom Fernanda.. Sem saber a fórmula da Vitamina B12, é IMPOSSÍVEL responder sua pergunta..
Estou aqui pra ajudar, mas ajude também com exercícios corretos, vai ?!
Obrigado.
Ah.. Se vc fornecer tbm a massa molar da vitamina e a massa molar do cobalto, dá pra fazer seu exercício. Ao menos algum desses dado o exercício deve dar, e não é atoa.
Valeu
OI, olha dá para resolver o exercício sim !!!!!
O que falaram antes é verdade apenas para facilitar você descobrir como se faz, porém ai tem dados que não levaram em conta.
Você tem o valor da massa total que é 1,5g de vitamina B12, e o cobalto tem 4,34% da massa dessa vitamina. Assim 4,34% de 1,5g é 0,0651g de cobalto, ou ainda em notação científica que facilitará as contas você terá 6,51×10-2 g.
Bom, agora que já sabemos quanto em massa há de cobalto na amostra de vitamina B12, temos de saber quantos átomos de cobalto há nessa amostra. Sabemos que um mol de algum elemento equivale a 6,02×1023 átomos e um mol de cobalto equivale a 58,9332g. Com isto agora é fácil desenvolver a conta e chegar no resposta esperada. Como são diretamente proporcionais, é só aplicar a famosa regra de três.
Assim temos:
58.9332g ——————— 6,02×1023 átomos
6,51×10-2 ——————— x átomos
Multiplicando em cruz:
58,9332.x = (6,02×1023).(6,51×10-2)
58,9332.x = 3,91902×1022
x = 6,64993586×1020 átomos
Portanto aproximadamente 6,65×1020 átomos de cobalto em 1,5g de vitamina B12.
(técnico em química)
Parabéns Lucas, matou à pau.
E André, veja se pensa um pouco mais simples da próxima vez… NÓ CEGO
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