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Exercício de grau de pureza

por sandra rodrigues (jogo de partículas) Fácil Friday, April 19th, 2013

Exercício:

calcule o aumento de peso de uma amostra de magnésio com um grau de oureza de 90% e uma massa de 3,24g quando oxidado completamente de acordo com a seguinte eq quimica:

 

2Mg(s) + O2(g) —> 2MgO (s)

Informações Adicionais:


Respostas:

11 Respostas a “grau de pureza”

jaspion diz:
Fady João Pedro diz:

Bom! atendendo as condiçoes do exercicio;
2Mg+O2>>>>2MgO
primeiro vamos buscar a amostra de magnésio a 90% 
ou seja 100%>>>>>3.24g
                 90%>>>>>>x
x=2,916g(Mg). depoi vamos fazer a relaçao e massas de magnesi e oxido de magnesio cuja proporção é 2:2 
2*24,31g(Mg)>>>>>>>2*40,31g(MgO)
2,916g(Mg) >>>>>>>> x  logo: X=4,836g(MgO).
como o Exercicio pede o aumento de peso de uma amostra de magnesio quando oxidado completamente, então temos:
a massa do aumento sera Xm =4,836-2,916 =1,92g

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