para racionalizar vc deve multiplicar o numerador e o denominador pelo denominador.a)3/4√5 = (3 . 4√5) /(4√5 . 4√5 ) = 12√5/16√25 = 12√5/(4 . 5) = 3√5/5

b)3√2/2√3 = (3√2 . 2√3)/(2√3 . 2√3) = 6√6/4√9 = 3√6/( 2. 3) = (√6)/2

c) √12/5 = (√12 . √5)/ (√5 . √5) = √60/√25 = 2√15/5

 
vlw 😉

eu ñ sei!
mais um dia quem sabe eu aprendo!

a;    3/4√5 X 4√5/ 4√5 = 12√5/80= 3√5/ 20
b;    3√2/ 2√3 X 2√3/2√3 =6√6/12= √6/2 c; não tem raíz no denominador , então não pode-se mexer

a:3/4√5 =3√5/4√5² =3√5/4.5 =3√5/20
b:3√2/2√3 =6√6/4√3² =6√6/12 =3√6/6 = √6/2
c: Não tem como fazer pois nao tem raiz no denominador
Na b pra quem não entendeu eu simplifiquei fiz passo a passo pra vocês notarem
Otimos exercicios 

a A) a B) e a C) eu não sei rsponder pois eu sou desconhecido OH…
KSKSKSKSKSKSKSKSKKSKSKSKSKSKS…
FLW!!! Boa sorte para resolver vcs!!!

Quee idiotisse, isso é  COISA DE NERD ! Vooc’s são taão mongoos –‘

___√2___
2√3+√6

so nerd aki galera so emo

a letra b de todos estão errados!!!
faz assim:
 
b) (3√2) / (2√3) = (3√2 * 2√3) / (2√3 * 2√3) = (6√6) / (2 * 3) = (6√6) / 6 ==> √6

2–√3

Poderia ter resultado né?
O meu A deu “3 raiz de 5 sob 20” tá certo? tenho mt dificuldade com isso

a)resposta-  3√5/20
b)resposta-  √6/2
c)nao precisa ,pois o denominador é real

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