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Exercício de Reação química
Exercício:
Considere a reação química representada pela seguinte equação:
4NO2 (g) + O2 (g) ——> 2N2O5 (g)
Num determinado instante de tempo t da reação, verifica-se que o oxigênio está sendo consumido a uma velocidade de 2,4 . 10-² mol L-¹ s-¹ . Nesse tempo t, a velocidade de consumo de NO2 será de:
(A) 6,0 . 10-³ mol L-¹ s-¹
(B) 1,2 . 10-² mol L-¹ s-¹
(C) 2,4 . 10-² mol L-¹ s-¹
(D) 4,8 . 10-² mol L-¹ s-¹
(E) 9,6 . 10-² mol L-¹ s-¹
Ajuda por favor!!!!!
aA+bB-> cC + dD
Vm = VA/a = VB/b =..
2,4.10-2/1= x/4
x= 9,6.10-2, sendo x a velocidade de consumo de NO2
n entendi pn o.Oé de qe série esse exercício ?
quero responder
tempo= indeterminado;
Oxigênio demora: 2,4…
E só vc multiplicar por 4 o valor do tempo do oxigênio;
Resultado: 9,6….
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