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Exercício de Títulos - Química
Exercício:
O título de uma solução é 0,25, calcule a massa do soluto, já sabendo que a do solvente é de 60g
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t=m1
M
onde m1= massa do soluto
M= massa da soluçao (soluto + solvente)
0,25 = m1 = 0,25m1 + 15 = m1
m1 + 60 m1 – 0,25m1= 15
0,75m1 = 15
m1= 20
Duda
Vc So Erro Em Uma Coisa o m1 a questao diz
Calcule a massa do soluto ou seja= M1 ou seja vc arrumo o m1 como solvente!A Respota Sera A Mesma Mais O Calculo E Diferente Ficara Assim
*1 E Melhor Fase uma Regra De Tres
Titulo:0.25(Trasmforma em real %) 0.25×100=25%
M2=60G
Total %=100 Ou Seja 25% de 60=?? (20G)
20G(25%)+20G(25%)+20G(25%)=75%
Massa Do Soluto
M1=20G
Me Chamo Raphael E Fasso 2 Ano Escola Publica =)
17/03/2011
formula: T= m1/m ficará: 0,25= m1/m1+60
onde T: 0,25 m1=0,25m1+15
soluto m1? m1 – 0,25m1 + 15
solventem m1+60 m1= 15/0,75 =20g
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